scenehouser

Hey guys,

I'm designing the Fuel System for my Vortech project and I have a question about the Walbro 255 fuel pump.

Does the Walbro pump more fuel because it is more efficient at the same voltage than the oem pump OR is it just as efficient but it can handle a higher voltage thus work harder?

Thnx.

maXmood

iTrader: (16)

you mentioned 255.. do you know what does that refer to? it means 255 lph (liter per hour). i don't remember what's the stock lph, but i'm sure it's way less.

secondly, a greater voltage is better, but the stock one will work just fine.

scenehouser

thnx for your reply but you didn't answer my question.

djamps

iTrader: (1)

Walbro flows 255lph. Stock flows less. Same voltage.

tonyzS/C03

iTrader: (3)

^+1 flows more period... i ran my stock fuel pump with my Vortech for ever, untill i decided to up the boost and injector size. If your just running the 3.33 pully and the split second box the stocker will do just fine. IMO if your doing diff injectors might as well do the fuel pump too.

spitalul2bad

I think you're all missing the question. He's asking about Walbro's engineering. He knows it flows more (255lph vs. 90lph stock). He's asky WHY / HOW does it do so versus the stock pump.

tylerxfire

iTrader: (15)

what is ur complete setup..vortech and all..ill let ya know if u even need a 255

350Z400rwhp

iTrader: (4)

I would imagine it has bigger internal components and or may draw more amps running at a higher speed and thus is more powerful at the same voltage than the stock fuel pump. That's just my best guess but at least I tried to answer your actual question.

djamps

iTrader: (1)

Correct.

It isn't 'more efficient', it just uses more amps at the same voltage (more power), thus pumping more liters of fuel per hour.

Think of it like a 4 ohm vs 8 ohm subwoofer - the 4 ohm will drain more power from the amp and output more bass, than an 8 ohm woofer on the same amp and volume level.

str8dum1

iTrader: (11)

umm its a physically bigger pump. bigger pump = more fuel.

mx594

iTrader: (4)

P=IV

Power = Current * Voltage

Given similar efficiency - which I assume they would be because they are of the same basic design and a similar size - then the only way to pump more fuel (at the same pressure) is to increase the power. Voltage is controlled by the alternator so we can consider it a constant in this example - so the only way to increase power is to increase amperage.

And I'm pretty sure the stock pump flows closer to 190 Lph - not 90 Lph.

scenehouser

okay thats very clear thnx (:

mx594

iTrader: (4)

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