Dual Voice Coil "Math"
#1
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I just noticed a dual 2 ohm sub can either have 1 ohm or 6 ohm if I remember correctly. That doesn't make sense to me. I am thinking of doing an MTX woofer setup with a matching amp. I can get the MTX 10" woofer in a single 4 ohm voice coil (which I would imagine puts out 4 ohms), or the dual 4 ohm voice coils. (which I am hoping if wired correctly allows for 2 ohm resistance).
Here are the basic specs for RMS
MTX 8500 T8510-44 (Sub) - 500 watts RMS
MTX Thunder TA91002 (Amp) - 2x500 @ 2 Ohms
Wouldn't this work in my favor???
Here are the basic specs for RMS
MTX 8500 T8510-44 (Sub) - 500 watts RMS
MTX Thunder TA91002 (Amp) - 2x500 @ 2 Ohms
Wouldn't this work in my favor???
#2
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You've got your math wrong.
In series resistances add so 2 + 2 = 4 ohm
In parallel resistances divide so 1 / 1/2+1/2 = 1 ohm
When dealing with two equal resistances just remember that the total resistance is going to be have of one of the loads. Makes sense because now the power has two paths to travel through meaning that the total resistance has to go down.
So yes, if you wire your dual four ohm sub-woofer in parallel (negative to negative and positive to positive) then you'll end up with a two ohm load for your amplifier which will thank you for the reduced load by putting out more power for you.
In series resistances add so 2 + 2 = 4 ohm
In parallel resistances divide so 1 / 1/2+1/2 = 1 ohm
When dealing with two equal resistances just remember that the total resistance is going to be have of one of the loads. Makes sense because now the power has two paths to travel through meaning that the total resistance has to go down.
So yes, if you wire your dual four ohm sub-woofer in parallel (negative to negative and positive to positive) then you'll end up with a two ohm load for your amplifier which will thank you for the reduced load by putting out more power for you.
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Originally Posted by Paul350Z
You've got your math wrong.
In series resistances add so 2 + 2 = 4 ohm
In parallel resistances divide so 1 / 1/2+1/2 = 1 ohm
When dealing with two equal resistances just remember that the total resistance is going to be have of one of the loads. Makes sense because now the power has two paths to travel through meaning that the total resistance has to go down.
So yes, if you wire your dual four ohm sub-woofer in parallel (negative to negative and positive to positive) then you'll end up with a two ohm load for your amplifier which will thank you for the reduced load by putting out more power for you.
In series resistances add so 2 + 2 = 4 ohm
In parallel resistances divide so 1 / 1/2+1/2 = 1 ohm
When dealing with two equal resistances just remember that the total resistance is going to be have of one of the loads. Makes sense because now the power has two paths to travel through meaning that the total resistance has to go down.
So yes, if you wire your dual four ohm sub-woofer in parallel (negative to negative and positive to positive) then you'll end up with a two ohm load for your amplifier which will thank you for the reduced load by putting out more power for you.
remember series is add and parallel you divide. so a dual voice coil will give you 4ohm in series. a dual voice 2ohm coil will sound beter than a single coil 4ohm speaker. GO DUAL COIL PLZ
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