I just noticed a dual 2 ohm sub can either have 1 ohm or 6 ohm if I remember correctly. That doesn't make sense to me. I am thinking of doing an MTX woofer setup with a matching amp. I can get the MTX 10" woofer in a single 4 ohm voice coil (which I would imagine puts out 4 ohms), or the dual 4 ohm voice coils. (which I am hoping if wired correctly allows for 2 ohm resistance).

Here are the basic specs for RMS
MTX 8500 T8510-44 (Sub) - 500 watts RMS

MTX Thunder TA91002 (Amp) - 2x500 @ 2 Ohms

Wouldn't this work in my favor???

 

You've got your math wrong.

In series resistances add so 2 + 2 = 4 ohm

In parallel resistances divide so 1 / 1/2+1/2 = 1 ohm

When dealing with two equal resistances just remember that the total resistance is going to be have of one of the loads. Makes sense because now the power has two paths to travel through meaning that the total resistance has to go down.

So yes, if you wire your dual four ohm sub-woofer in parallel (negative to negative and positive to positive) then you'll end up with a two ohm load for your amplifier which will thank you for the reduced load by putting out more power for you.

 

+1

remember series is add and parallel you divide. so a dual voice coil will give you 4ohm in series. a dual voice 2ohm coil will sound beter than a single coil 4ohm speaker. GO DUAL COIL PLZ

 

also if your speakers can handle 500 watt rms then get a stronger amp. usually a 1000 watt amp will only have an rms of 300-400. so if you are going to run 2x 500watt rms speakers get atleast a 2k watt 2ch amp.

 

This site's illustration might also help...

http://mobile.jlaudio.com/support_pages.php?page_id=161

 

Here you go...

 

Or for parallel, product/sum if it's easier to do that in your head.