not only that, but rechecking. I get that

a = (vf-v0)/t

350z acceleration = 10.36 ft/s^2
civic acceleration = 8.26 ft/s^2

Also... interesting. measure the distance between a STI and 350z..

STI 13.2 @ 100mph
350z 14.0 @ 102mph

 

Well it can't be too "largely inacurate" since it is awfully close to the 13 car lengths you stated earlier. Assuming acceleration is constant is the ONLY way I'm going to do the caluclation.

I'm not going to do intergral calculus to derive a solution with this many unknowns. Heck, can I assume rolling w/o slipping too.

For the guy who asked, I'm a Mechanical Engineer at Lockheed Martin. I'll take my cookie and bolt now... Later!

 

figured you were an ME somewhere...... I am ME too...... except i work in the water industry (equipment manufacturing of water treatment equipment and process design), so i don't get to use my schooling too much, i use civil type stuff all the time though. oh well

 

you can't assume rolling without slippling either! it's a dragrace

J/K

 

I'll reformulate the Q:
What distance did Civic travel in last 1.6s of its run, where ending speed was 88.4mph?

Answer is between 13 and 15 car lengths, depending on cars' CD, wind direction, Civic's gear/rpm/power/torque, etc.

Since we don't know starting speed of Civic (at beginning of 1.6s interval) and we don't know average accel during that time (we need either one), we cannot precisely calc the distance travelled.

Another assumption is that Civic travelled in straight line, but that's prolly true .

Cheers.

 

all physicists have a love affair with frictionless planes... jeez

 

If a 350z revs it engine and no one is there to hear it, does it make a sound?

 

does this 350z have a mind of its own

 

 

The driver of this particular 350z happens to be deaf.

 

well then obviously the answer is it must of had a loud a$$ exhaust

 

OKAY.....I raced one this morning (he started it) and the real-world answer is a hell-of-a-lot-more-than 16 car lengths.