technical ? about building a sub enclosure
If I have a sub enclosure that is one single chamber and I'm trying to determine the tuning frequency:
do (2) 3"(diameter) by 4.5" (length) ports equal a 6" (diameter) by 4.5" (length) port or a 3" (diameter) by 9" (length) port?
do (2) 3"(diameter) by 4.5" (length) ports equal a 6" (diameter) by 4.5" (length) port or a 3" (diameter) by 9" (length) port?
Using the basic mathematical equation to find the area of a circle [A=pi(r^2)]:
The area of ONE 3" port is 7.065"
The area of TWO 3" ports is 14.13"
The area of FOUR 3" ports is 28.26"
The area of ONE 6" port is 28.26"
So two 3" ports do not equal one 6" port in area.
The area of ONE 3" port is 7.065"
The area of TWO 3" ports is 14.13"
The area of FOUR 3" ports is 28.26"
The area of ONE 6" port is 28.26"
So two 3" ports do not equal one 6" port in area.
I have an enclosure that looks similar in shape to a zenclosure... it is an mdf/fiberglass mix that stops just before the space under the rear strut bar... you can't get an idea of its shape without looking inside... I'd say the true internal volume is around 1-1.15 cubic ft (sealed)without the driver... I have a RF HX2 10 being driven by a bridged Crossfire 402 (400X1)... it sounds like a** with too much airspace being sealed for my sub... I bought (2) 3"X4.5" ports and (2) 2.75"X5.25" ports and want to see if I can get a better sound out of it before buying something else... trick is that it's only about 8" deep
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Originally Posted by atlantavip
If I have a sub enclosure that is one single chamber and I'm trying to determine the tuning frequency:
do (2) 3"(diameter) by 4.5" (length) ports equal a 6" (diameter) by 4.5" (length) port or a 3" (diameter) by 9" (length) port?
do (2) 3"(diameter) by 4.5" (length) ports equal a 6" (diameter) by 4.5" (length) port or a 3" (diameter) by 9" (length) port?
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