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Old 04-11-2007, 07:04 PM
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JYear
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Default Ohm question...

I believe the JL 10w3v2-d4 sub I have now is wired as such...



Would anyone know what Ohm that produces? Is it wired in a correct manner? I purchased it this way...so I'm wondering.

Thanks for the help.
Old 04-11-2007, 07:21 PM
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starvinmrvn
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Looks Wrong to me... u left out a (-) But looks like series....so 8ohm

Besides that looks like a Rockford Fosgate Sub to me

http://mobile.jlaudio.com/support_pages.php?page_id=163

I just installed JL 10w6v2 today...PM me if u need anything else
Old 04-11-2007, 08:12 PM
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JYear
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Yeah, that picture is a RF sub...just for reference of how it was wired.
Old 04-11-2007, 09:23 PM
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KelekonaKustoms
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yeah that looks wrong, what amp do you have? if you only have the one sub i would advise that you wire it parrallel which would give you a 2ohm load.
Old 04-12-2007, 07:09 AM
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DVFlyer
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That is 4ohm... only one voice coil is connected. The jumper to the other voice coil isn't doing anything because nothing is connected to it's negative side.
Old 04-12-2007, 10:05 AM
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infamous350
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yeh run it at 2ohm if its one sub just do it negative to negative and positive to postive
Old 04-12-2007, 10:32 AM
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Quick modification to your pic to illustrate hook up differences.
Attached Thumbnails Ohm question...-series-hook-up.jpg   Ohm question...-parallel-hook-up.jpg  
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